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A puzzler

If there were four different answers, it would be 25%, or one in four.
Since 25% occurs twice, then on that basis both A) and D) would be correct.
In that light, there are two 'correct' answers, thus it would be that 50% of the answers
count as correct.
But then 50% is a correct answer, but only if 25% is also correct twice. Yeah, what a
conundrum.
 
Well, if you choose randomly then it must be because you think 25% is correct but there are two 25% answers so you randomly choose between A and D. Since 25% is wrong, you have a 100% chance of being wrong and therefore a 0% chance of being right; therefore the correct answer is B. Who would choose B randomly when that gives you a 0% chance of being correct?

(Which is to say, "choose at random" is an incomplete problem description because it doesn't specify the probability distribution.)
 
The question itself doesn't have a correct answer. That means that you can't get a correct answer and that therefore B: 0% is correct.
But if choose an answer at random then you have only 25% chance of selecting B, therefore 25% is the correct answer.
But because two options have 25% as their answer, then you have 50% chance of getting the "correct" answer, which would make C 50% the correct answer.
But we already know that getting the "correct" answer of B is only 25%, so we can't determine the chance of getting a "correct" answer (it is indeterminate), and anyway as I stated originally the question is not of a type that can yield a correct answer.
So there is no correct answer to this question, which means you have 0% of answering it correctly ....

The question can't be answered by choosing an option from the four listed, but only outside of that "answer space". The only way to win is not to play.
 
Put 4 colored balls in box. 1 red(25%), 1 red(25%), 1 blue(50%), 1 green(0%)

Shake the box pull a ball, put the ball back in, and repeat.

Each ball will average out to 25%.

red(25%) will be picked 50% of the time.
green(0%)( picked 25% of the time
blue(50%) will be picked 25% of the time.
 
The question itself doesn't have a correct answer. That means that you can't get a correct answer and that therefore B: 0% is correct.
But if choose an answer at random then you have only 25% chance of selecting B, therefore 25% is the correct answer.
But because two options have 25% as their answer, then you have 50% chance of getting the "correct" answer, which would make C 50% the correct answer.
But we already know that getting the "correct" answer of B is only 25%, so we can't determine the chance of getting a "correct" answer (it is indeterminate), and anyway as I stated originally the question is not of a type that can yield a correct answer.
So there is no correct answer to this question, which means you have 0% of answering it correctly ....

The question can't be answered by choosing an option from the four listed, but only outside of that "answer space". The only way to win is not to play.

Kobiyashi Maru!
 
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