Phil Scott
Member
Weere you given a proof? Rigorously showing that the reals form a continuum would require a rigorous definition of "continuum." What we have instead is rigorous definitions for things like "real number" and "hyperreal number". Whether these collections get at the nature of the continuum is more into the metaphysicals (as Speakpigeon observed).This was originally about whether or not the reals form a continuum. I was taught that they do in a very rigorous calculus course.
Which claim in particular? I'm afraid I won't be giving references for what is undergraduate level mathematics. I can link you to my PhD thesis in formalised mathematics (where the rigor is dialled as high as it goes), and if that's not enough, I'll just leave you folks to it.So I need some reference that your claim is true.
The equals symbol is, as you say, just the equals symbol. It's used to say that the two expressions on either side denote the same object.As for the equals symbol. Like I asked Juma, is it only an equals symbol for reals? If so, then I have no issue with 1 = 0.99.... If not, then the previous claims about 1 not being the same as 0.99... using hyperreals naturally concerns me when I see 1 = 0.99....
The hyperreals are a proper superset of the reals, and so you will still use your decimals to refer to the subset of the hyperreals which are real. To refer to finite non-real hyperreals, you need to state what the infinitesimal part is.