Malintent
Veteran Member
Just for fun, I decided to work out the probabilities.
From what I've found online, $1 slots have a house advantage of about 10%, with a single wager payout standard deviation of about $5.
That means that, for the 90% payout slots, after 100,000 spins you should expect to lose $10,000 with standard deviation of around $1581.
To be honest, I was a little surprised at how high the standard deviation is, but, on second thought, high volatility makes the games more fun for the player and the casino can afford to wait and let the law of large numbers do its thing.
40 million people visit Vegas each year, and I'd guess that on average it's $100 in slot pulls each? More?
That would mean the casinos should expect to make $400,000,000 in profit on slots in a year with standard deviation of only $300,000. That's crazy.
When the Treasury Casino opened in Brisbane, I went to have a look around with a mate. He said "I have a system for playing roulette; I can't lose". I said "Take a look around. Plush deep carpets; crystal chandeliers; expensive paintings on the walls; Cheap food and drink; loads of staff everywhere; all of this costs a LOT of money. Do you think that this place would look like this, if there was a system where the punter 'can't lose'?".
The only casino that I would patronise as a gambler would be one where they were about to shut down due to bankruptcy. That's at the minimum indicator that the house doesn't have an edge. Even then, I would suspect that their problems didn't arise because the odds were against them.
While casinos are glitzy, it is clear that Mr Burns had the business model all worked outC. Montgomery "Monty" Burns said:Well, I've discovered the perfect business: people swarm in, empty their pockets, and scuttle off.
I know that 'trick' to 'never losing' at roulette. The 'trick' relies on vey high (or non-existent) house betting limits.. .which, is precisely how the casinos avoid bankruptcy... So they set table limits very carefully to prevent this trick from working.
This is the method:
always bet the minimum table bet on a color (black or red).
if you win, do it again.
If you lose, make your next bet DOUBLE your last bet, plus the table minimum
repeat that until you win
once you win, go back to the minimum bet
Let's say the minimum bet on a particular roulette table is $10. That table would then have a MAXIMUM bet of $1,000.
Choose a color (black or red).. let's just say we choose black.
on your first bet, put $10 on black.
If you win, you will profit $10, and you bet $10 again.
If you lost your first bet, put $30 on black for your second bet (double your last bet + minimum)
if you win, you will have profited $20 ($30 win - $10 loss)
If you keep doing this, you will earn $10 per spin of the wheel, no matter if you win or lose...
UNLESSS!!!!!!!!!!!!------
the wrong color comes up 6 times in a row. Then you are fucked.
loss 1: $10
loss 2: $30
loss 3: $70
loss 4: $150
loss 5: $310
loss 6: $630
You cannot make your 7th bet, as it would exceed the house limit. At this point, you have lost $1,200, and cannot make an appropriate bet to recover it.
So, this tick relies on answering the following question for yourself....
will the same color appear on the wheel 6 times in a row before you have played 120 times... by your 120th spin, you will have profited enough to cover a 6-in-a-row-defeat.