Because 2 is the next whole number after 1.
Well, yeah.
You have the alternating harmonic series.
Every alternating reciprocal simplex series has log(2) in it.
It pops up elsewhere:
For limit n-->infinity x=x^n-1 (positive real root, so x^n ~2) k-->infinity nestings
\(\sqrt{log(2)}= \lim_{n\to\infty} \,\, \sqrt{\left(nx^{n-1}\right)^k \,\, \times \,\, \left(x-\sqrt[n]{1+\sqrt[n]{1+\sqrt[n]{1+\dots}}} \right)}\)
if you set n=2, and x=x^2-2 (positive real root)
\(\frac{\pi}{2}= \,\, \sqrt{(4)^{k} \,\, \times \,\, \left(2-\sqrt{2+\sqrt{2+\sqrt{2+\dots}}} \right)}\)
There has to be an explanation as to why pi/2 pops up after the square root of the natural log of number 2 when using infinitely nested radicals to calculate both. Infinitely nested radicals... lemme see. Natural log of #2 is all evil, so the root of all evil is an infinitely nested radical equation... who is the infinitely nested radical?
And my computer is rooted... love the shady people... sooooo much.