Jokodo
Veteran Member
Then why are you talking about performing arbitrary operations to 9/1 in a discussion of 1/9 as if there is any relationship?
Where am I?
You have a bunch of rounding tricks and nothing else.
You keep saying this, but can't point to a single one of them.
Of course it does. 0.04 in base 6, or 0.14 in base 12. The fact that it is not possible to express this value without somehow marking recursion in base 10 is a bug of base 10 notation, nothing more, nothing less. Definitely not a property of the number itself
1/9 is an operation. Not a number. You confuse operations with numbers.
And the operation never reaches a final value.
There is no final value to 1/9.
Of course there is, the question is only how to represent it in a given language such as the language of decimal notation. The decimal systems is not particularly well suited to precisely express fractions with a denominator that's a multiple of three because it's base, 10, does not include 3 as a prime factor. The duodecimal system is better suited for this purpose, but runs into similar problems with denominators that are multiple of five, and which are unproblematic under base 10. This doesn't say anything about the number itself. Your ability to cut a rod into nine sticks of equal length solely depends on the precision of your measuring and cutting tools, not on whether its initial length was one yard (yielding 9 sticks of exactly four inches each) or 1 metre (yielding nine sticks of 11.(1) cm).
It cannot be changed to some other base and retain all it's features. It a specific entity not any other entity.
You want to change it or perform rounding operations to it.
Not at all. I'm actively refusing to round it.
That is all you are doing.
Do you even know what "rounding" means?
Yes.
Rounding occurs when you pretend an infinite operation has completed.
Like when you pretend there is a final value to 9 * 0.1111...
That operation never finishes.
It finishes as soon as you've determined that the validity of the equation "1*10^n * 9 = 9*10^n" is independent of the value of n, which is a tautology. At that point, you know that, as long as the input contains no non-0, non-1 digits, the output has a "9" wherever there was a "1" in the input. As we defined ellipsis to mean "only '1's hereafter", the result follows per the definition of the input.
This method is no different in principle (rather, quite a bit more basic) from using long multiplication to derive the result of, say, 70 * 1100. Are you also claiming that the result 77,000 for this operation is valid only if I actually did at least 70 additions and record all intermediate values (and preferably 1100 -- who knows whether multiplication really is commutative)?
When you claim it does and by magic it somehow reaches 0.999... you have rounded off.
You have been taught to deal with infinities by pretending they are not there or by pretending they can complete. So you never see the irrationality in how you deal with them.
Do you understand that the decimal system is not the numbers
I am not talking about the decimal system.
I am talking about a specific entity. 0.999....
As defined it has no final value. There is no last 9.
The entity "0.999..." the way you are using it is a string. A string that could be a password on a server that doesn't require passwords to contain letters, that could be a partially masked credit card number, that could refer to "let's bomb the white house" in a code language you use to communicate with your co-conspirators, or any number of other things in any number of other actual or conceivable symbol systems aka languages.
In a limited (though still potentially infinite ) number of languages, in positional number systems with a base b > 9.0, 0.999... refers to a number. What number it refers to depends on which system you're looking at: For example 9/B12 (=9/1110) in duodecimal, 9/F16=6/A16=3/516 (=6/1010=3/510) in hexadecimal (note how this actually has a final representation in decimal?), and 9/9=3/3=1/1 in decimal. More generally, it will always be 9/(b-1). Whenever (b-1) is divisible by 9 or 3 and the result of that division has no prime roots not also contained in the base, the result has a finite representation in that base*, otherwise it doesn't. However, that tells you something about that particular base (for decimal, that the base's prime roots are 2 and 5) and nothing about the number.
The entity referred to by the string "0.999..." in the arbitrary language that is the decimal notation is every bit as finite as the entity referred to by the same string in hexadecimal. The fact that 6/10 doesn't have a representation that can be explicitly enumerated in finite time in base 16 doesn't make the number more commonly known as 0.6 any more infinite than the fact that 1/9 cannot be in decimal makes that number infinite.
Except if you believe that the decimal notation -- and only the decimal notation -- has a special intimate relation to the numbers themselves.
* Assuming the arbitrary convention that recurring 0s need not be marked as such.
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