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y² = – 4ax


Equation of path of projectile motiony = (tan θ0)x – gx2/2(v0cosθ0)2
Time of maximum heighttm = v0 sinθ0 /g
Time of flight2tm = 2(v0 sinθ0/g)
Maximum height of projectilehm = (v0 sinθ0)2/2g
 
y² = – 4ax


Equation of path of projectile motiony = (tan θ0)x – gx2/2(v0cosθ0)2
Time of maximum heighttm = v0 sinθ0 /g
Time of flight2tm = 2(v0 sinθ0/g)
Maximum height of projectilehm = (v0 sinθ0)2/2g
A for effort. Winner.
 
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